General Mechanical

General Mechanical

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Why DOF is looks like 3 DOF?(Modal Analysis with Linear)

    • dhulee
      Subscriber

      Hi there.

      I'm trying

      Interpreting cantilever structures with modal in ANSYS WB 2024R2. Both ends are free.

      The question is when we extracted the current mesh information and M, K matrices.

      Mesh>Automatic Method
      Element Order: Linear
      Node: 88
      Elements: 21

      At this point, the M and K matrices have a total of 264 rows and columns.
      If we divide this by the number of nodes, we get 3, and I think this 3 means dof.
      But I think it's a three-dimensional space and it should be 6 degrees of freedom, so does anyone know why this is coming out?

       

      I would appreciate it if you could tell me if any of the conditions mentioned are lacking. I'm not good enough because I'm an undergraduate, but I want to get better with advice.

      Thank you.

    • Erik Kostson
      Ansys Employee

       

      Hi

      You are using a 3D solid body, that will be meshed with 3D elemets (solid185) that have 3 dof (at each node), and not 6.

      See the help manual for more info on solid185 elements that are used when you set mesh to linear in modal analysis.

      All the best

      Erik

       

    • dhulee
      Subscriber

      Hi Erik!

      Thank you for letting me know which part of the helper manual it is.

      Therefore, it was found that the existing shape was extruded with a beam and had the same frequency in nodal solu.

      However, the number of elements is the same as 21, but the number of nodes is 43.

       

      I set it to be am at 3 degrees of freedom of solid and made it into 6 degrees of freedom, but I'm looking for why the number of nodes is different.

      Can you help me with this part, too?

       

      best lee

    • Erik Kostson
      Ansys Employee

      Using beams will generate additional mid-nodes .

      All the best

      Erik

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