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Visualizer里的参数意义Re lm abs angle

- September 6, 2024 at 12:57 pm
  
  2504909744
  Subscriber
  
  老师，您好。我有两个问题：1.就是我们在查看监视器的电场时，电场的表达式是E=Aexp[i(kr-wt)]还是复振幅E=Aexp(ikr)。 2. 根据欧拉公式exp(ix)=cosx+isinx 展开的话那Re是不是Acos(kr) 虚部为Asin(kr) abs=A angle =kr。谢谢
- September 11, 2024 at 1:35 am
  
  sidi.lu
  Subscriber
  
  您好，查看监视器时，电场为复数形式E(x,y,z) = A(x,y,z) exp [i phase(x,y,z)]，拥有Ex，Ey，Ez 三个分量。
  E=Aexp[i(kr-wt)]是波动方程平面简谐波通解。
  祝好，
  Sidi

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