LS-DYNA nodout time step

- July 7, 2023 at 8:12 pm
  
  Fady Elshazly
  Subscriber
  
  Hello,
  
  I am solving model explicitly and the input motion has a time step of 0.005 sec. I am trying to record the nodout in ASCII database at dt=0.01 sec and dt=0.0001 sec. Both models give different results. Is the nodout dt used in input interpolation and then used in the analysis? or what would make this difference.
  
  Thanks
- July 10, 2023 at 3:23 pm
  
  Andreas Koutras
  Ansys Employee
  
  Hello, output cannot be generated at time intervals less than the timestep size of the analysis. The smaller output time interval can output a higher frequency of the response. However, the results at the same time instances should be the same in the two cases.
  - July 10, 2023 at 7:33 pm
    
    Fady Elshazly
    Subscriber
    
    The analysis time step is 1*10-5 which is smaller than the two cases. The dt i am using to generate the output is used only for the nodeout and is smaller than the one for the d3plot. can this cause the results difference?
- July 11, 2023 at 12:16 pm
  
  Andreas Koutras
  Ansys Employee
  
  Hello Fady,
  Please see the above reply:
  The smaller output time interval can output higher frequencies of the response. However, the results at the same time instances should be the same in the two cases.
  - July 11, 2023 at 6:53 pm
    
    Fady Elshazly
    Subscriber
    
    Thank you so much