Learning Forum

[eric.s.bish]

Hi,

I'm working through the lecture unit "Structural Analysis of Beams with Ansys Discovery" and am setting up the exercise analyzing a cantilever beam with circular cross section as shown in slide 27.

The beam has a distributed load of 20 kN total force on a beam 1 m long. Hence 20 kN/m distributed load as shown in the figure.

What if I now change the beam length from 1m to 1.5m? Is the distributed load still 20 kN/m, or is it now 20 kN/1.5m = 13.33 kN/m?

Thanks! 

[Sahil Sura]

Hi Eric Bish,
When you apply a structural load like Force in Ansys Discovery, by default it gets distributed across the scoped geometry. Thus, when a distributed load is used, it resembles a force per unit area. 
Thus for the concerned case, if the distributed force is set to 20 kN, the force per unit length won't be the same for the beams with lengths 1m and 1.5m if defined as a total force.
So if you want to keep the force per unit constant, you need to adjust the total load proportionally. 

For more information, please refer to-
Force (ansys.com)
3D Design Courses | Ansys Innovation Courses

Hope this helps!
Thanks,
Sahil
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[eric.s.bish]

Got it. Thanks!

[BHARGAV VEMAVARAPU]

How to apply load at specific point in a bar which is imported from another modelling software 

[Sahil Sura]

Hello @BHARGAV VEMAVARAPU,
I would request you to create a new thread of discussion for the new query as our support engineers would be efficiently able to solve the same.
Hope this helps!
Thanks,
Sahil
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