Ansys Assistant will be unavailable on the Learning Forum starting January 30. An upgraded version is coming soon. We apologize for any inconvenience and appreciate your patience. Stay tuned for updates.

Innovation Space

FREE STUDENT SOFTWARE

Checking stabilization energy much less than 10% strain energy in buckling analysis – meaning

- November 9, 2019 at 11:40 am
  
  Gennaro
  Subscriber
  
  Hello everyone,
  
  in the slides of Ansys (attached) I read that, after the simulation, I have to check if the energy dissipation ratio (EDR) is greater than the EDR initially specified (slide 39).
  
  How can I do that? In the slide 43 the suggested check is:
  
  max stabilization energy << 10% strain energy
  
  This means that the strain energy coincides with the potential energy mentioned in the slide 39:
  
  EDR = (stabilization work) / (potential energy)
  
  ?
  
  Thank you in advance.
- November 9, 2019 at 10:46 pm
  
  peteroznewman
  Subscriber
  
  Does it clarify things if you know the following equality?
  
  Potential Energy = Strain Energy
  
  I think the slides introduced unnecessary terminology when they added potential energy. It would be clearer if the slides stayed with strain energy.
  
  EDR = Stabilization Energy / Strain Energy.
- November 10, 2019 at 7:23 am
  
  Gennaro
  Subscriber
  
  Hello Peter,
  
  I know the equality (I found it in many books; e. g. "The Finite Element Method and Applications in Engineering Using ANSYS® - Erdogan Madenci, Ibrahim Guven 2nd Ed"):
  
  Maybe your equality is valid in special cases. If you know any paper or book where I can find your equality, give me its name please because I need to explain my sentences to my professor.
  
  Thank you a lot.
- November 10, 2019 at 9:45 pm
  
  peteroznewman
  Subscriber
  
  Here is the ANSYS definition of Element Potential Energy, which for an elastic analysis is Strain Energy.
  There is a separate quantity for Work Done by External Loads.
  
  There is also Kinetic Energy, but for a Statics / Linear Bucking, there is zero velocity.
- November 11, 2019 at 8:23 am
  
  Gennaro
  Subscriber
  
  Hello Peter, thank you for your reply. Can you tell me where you took the above paragraphs please?
- November 11, 2019 at 9:36 am
  
  Aniket Chavan
  Forum Moderator
  
  https://ansyshelp.ansys.com/account/Secured?returnurl=/Views/Secured/corp/v195/ans_thry/thy_tool16.html
- November 11, 2019 at 9:57 am
  
  Gennaro
  Subscriber
  
  Hi Aniket, I am not able to open your first link. Can you tell me what is it please? If you write the key word you inserted in the help, I can find it.
- November 11, 2019 at 1:20 pm
  
  peteroznewman
  Subscriber
  
  If you are using ANSYS 2019 R3, then do this.
  
  1. From ANSYS Workbench, use the menu Help > ANSYS Workbench Help. A browser window will open.
  
  2. In the post that has a link to the ANSYS Online Help, Right Mouse Button on the link and select Copy Link Address,
  
  3. Go to the browser window that opened in step 1 and Paste in the address bar and you get to the required page.
- November 11, 2019 at 2:14 pm
  
  Gennaro
  Subscriber
  
  Perfect step by step solution. Thank you very much.

Viewing 8 reply threads

The topic ‘Checking stabilization energy much less than 10% strain energy in buckling analysis – meaning’ is closed to new replies.

[bingo_chatbox]