TAGGED: ansys-aqwa, ansysaqwa, aqwa
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July 31, 2024 at 10:54 amr.abbasiSubscriber
I am trying to model a linear connection with spring-damper characteristics, similar to a Power Take-Off (PTO) system, for a structure in AQWA. From my understanding, it's possible to use a cable with defined stiffness to model the spring behavior, but I haven’t found an option to incorporate damping.
To provide more context, the structure I am working with has a submerged section and is connected to a linear damper that only allows movement in the heave direction.
Could you advise on how to model the damping effect in AQWA?
i tried to use two fenders in different directions, but I don't know how!
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August 5, 2024 at 11:26 am
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August 6, 2024 at 6:13 am
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August 6, 2024 at 6:18 am
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August 6, 2024 at 8:12 am
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August 12, 2024 at 2:19 am
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August 12, 2024 at 8:03 amShuangxing DuAnsys Employee
Please check the normal direction of the fender, which should be pointed towards the fixed point.
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August 16, 2024 at 1:24 amr.abbasiSubscriber
Thank you for your guidance. I would appreciate it if you could help me understand the following questions as well:
Can we simulate the damping/stiffness of a Power Take-Off (PTO) system using just two fenders along the vertical axis, deactivating other degrees of freedom (DoF), instead of using eight fenders on two horizontal levels to restrict motions?
If we want to use a linear damper with no stiffness, such as a 5 N·s/m damper, what values should we input for the damping coefficient (with units in seconds) and for coefficient A (with units in N/m)?
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August 16, 2024 at 8:11 amShuangxing DuAnsys Employee
From 9.8.3. Fender Friction and Damping (ansys.com), equation (9.89), you may need to define a very small stiffness, for example k=1.0e-3 N/m, the input fender damping coefficient is 5 N.s/m / k = 5 N.s/m /1.0e-3 N/m = 5e3 s. Â
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August 19, 2024 at 3:11 am
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August 19, 2024 at 8:27 amShuangxing DuAnsys Employee
The force is the function of the length change, instead of the initial uncompressed size.
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