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Ansys Learning Forum › Forums › Discuss Simulation › Photonics › How to implement 50 Ohms output impedance of a PD? › Reply To: How to implement 50 Ohms output impedance of a PD?

December 11, 2024 at 8:57 pm
Kyle
Ansys Employee

The RFSA uses a default impedance of 1 Ohm for the power calculation, and unlike the PWM there is no option to change this. You can submit a feature request for this if you like at this link: https://ix.lumerical.com/

As a workaround, to get the results for 50 Ohms you can divide the power result of the RFSA (in Watts) by 50. You can do this in a post-processing script, or you could add an Electrical Constant Multiplier element in front of the RFSA with a gain of 1/sqrt(50) to renormalize the amplitude of the signal before the RFSA.