January 29, 2024 at 12:53 am

mdmech.mech

Subscriber

Hi Peter, From Internet, I have found a formula,

x = 0.025 m

acceleration =Â 4*Ï€^2*f^2*xÂ = 0.2467 m/s^2

I am not sure, which method is correct

**As you suggested,**

f = 0.5 Hz

A = 0.025 m/s

w = 2*pi*f = 3.14159 rad/sec

velocity = A*sin(w*t)

t = 2 seconds

acceleration = A*w*sin(w*t) ---- As you said I have taken the derivative

Â Â Â Â Â Â Â Â Â Â = A*(2 * pi * f) * sin(w*t)

Â Â Â Â Â Â Â Â Â Â Â = 0.025*(2*3.1416*0.5)*sin(3.1416 * 2)

Â Â Â Â Â Â Â Â Â Â Â = 0.00859 m/s^2

Please give me a suggestion as to which value of acceleration I should take.

The tank is half filled with free surface with air at the top.