General Mechanical

General Mechanical

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Why the sticking zone is not shown in the contact patch ?

    • hajar.rhylane
      Subscriber
      Dear community, I need your support about my simulation.
      I want to analyse the contact between a rolling wheel and rail as it is shown in the picture using ANSYS APDL but my results are not as was expected like specially the repartition of the stick and slip zones which is given in APDL by contact status. i don't know why there is no stick zone in the contact patch ? the contact status indicates always that the wheel is in sliding status even when the wheel is not moving. Please let me know if you have any suggestions or corrections to my issue ????????????????????????. The contact is frictionnal and symmetric. 
      To simulate the rolling motion of a loaded wheel, I defined three steps:
      -step1: the bottom side of the rail is fixed and symmetry boundary conditions are applied to the left side of the wheel and rail.
      -step2: the symmetry bcs are removed from the left side of the wheel and the the pilot node is free to move in vertical direction . the load (FZ=-75000N) is applied to the pilot node
      - step4 : translation velocity (Vx=50km/h) and angular velocity (Omgy)and are applied at the pilot node.
       
      Here is the code corresponding to these load steps:
       
      !Clamp the rail bottom
      asel,s,area,,42
      da,all,all  
      allsel,all
       
      ! Constrain symmetrical plane
      asel,s,area,,17
      asel,s,area,,37
      asel,a,area,,40
      da,all,UX 
      da,all,Uy 
       
      !fix the pilot node
      D,NODENUMBER+1,all
       
      allsel,all
      eplot
       
      Finish
       
      !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
      /SOLU   
      ANTYPE,4
      nlgeom,on
      TRNOPT,FULL,,,,,NMK
      TINTP,HISP!GAMMA = 0.005
      KBC,0 
      RESCONTROL,,NONE,None 
      autots,off
      OUTRES,ALL,ALL
       
      !step1 charging a static wheel  
      Time,0.001 
      DELTIM,dt,dt,dt
      TIMINT,off   
      DDele,NODENUMBER+1,Uz
      F,NODENUMBER+1 ,FZ,-Cn 
      Allsel  
      Solve   
       
      !step2 rolling 
      !inserting speed values  
      Time,0.002 
      DELTIM,dt,dt,dt 
      TIMINT,on  
      asel,s,area,,17
      DADELE,all,ALL 
      D,NODENUMBER+1,omgy,Wr
      D,NODENUMBER+1,velx,V
      Allsel  
      SOLVE   
       
      !pick up solution stage d=115mm
      Time,0.00978
      DELTIM,dt,dt,dt  
      TIMINT,on 
      Allsel  
      SOLVE  
      Please find attached the contact status corresponding to the last set of :
      -Charging stage:
      - Rolling stage
      Best regards,
    • mrife
      Ansys Employee

      Hi Hajar

      Double check the contact real constants; perhaps the limit frictional stress or contact cohesion values are not set as you intended.  Mike

    • hajar.rhylane
      Subscriber

       

      Thank you so much sir Mike for your too much important answer.
       
      You have recommended to me to check the maximum friction stress (TAUMAX) value considered in the contact settings and i found that TAUMAX was equal to 1 in my simulation. I need to ask you sir what is the formula should be used to calculate the TAUMAX value that i should input in the contact settings?
       
      According to the ANSYS manual:
      ” The program provides one extension of classical Coulomb friction: real constant TAUMAX is maximum contact friction with units of stress. This maximum contact friction stress can be introduced so that, regardless of the magnitude of normal contact pressure, sliding will occur if the friction stress reaches this value. You typically use TAUMAX when the contact pressure becomes very large (such as in bulk metal forming processes). TAUMAX defaults to 1.0e20. Empirical data is often the best source for TAUMAX. Its value may be close to the yield stress of the material being deformed devided by squar(3)”.
       
      In the case of my simulation the yield stress of the steel is 489MPA so i defined TAUMAX as follow: RMODIF,3,9,282.324281633727e6. This value is yield stress divided by squar (3). Is this correct sir?
       
      I’m really confused about its value please guid me.
       
      Thank you so much sir,
      Best regards
      Hajar
       

       

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