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August 13, 2022 at 3:51 am
smzia
SubscriberHi,Greetings. I would like to ask about the "T" attribute in Lumerical FDTD. Does it mean power transmission or electric field transmission? Could anyone please give any idea with explanation and proof?Regards,Zia -
August 15, 2022 at 5:55 pm
Guilin Sun
Ansys EmployeeHi Zia,
It is power transmission, the same as the script command "transmission":
https://optics.ansys.com/hc/en-us/articles/360034405354-transmission-Script-command
Please note that it uses the Poyntine vector dot surface normal, and the surface normal is always defined as along positive axis. Therefore the result can be negative. However it does not mean the reflected or transmitted power is negative.Its sign is to be used for other purpose, for example forward and backward propagation.
I hope this helps.
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August 15, 2022 at 8:25 pm
smzia
SubscriberThank you so much for the answer. It's truly helpful.
Regards,
Zia
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August 19, 2022 at 4:08 pm
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August 19, 2022 at 8:47 pm
Guilin Sun
Ansys EmployeeAbs=absolute value
Abs^2 is the square of the abs value.
In the case of transmission, they are not useful.
the Visualizer is designed for visualizing all quantities so there are many operations.
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August 19, 2022 at 9:59 pm
smzia
SubscriberHi Guilin,
So, which will visualize power? Real value of T? I have found that Real value of T and Absolute value of T gives the same value.
You have already mentioned T is power transmission, So real value of T or absolute value of T should give the power transmission result? Isn't it?
I think, If T is electric field then Abs^2 or square of abs value would represent the power then.
Like if T is power then Abs(T)/Re(T) will visulize power transmission.
if T is electic field then, Abs^2(T) will visulaize power transmission. As , P=E^2.
Please let me know your thoughts.
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August 22, 2022 at 4:13 pm
Guilin Sun
Ansys EmployeeT is real valued so Real value of T and Absolute value of T gives the same value.
T should give the power transmission result.
" If T is electric field then Abs^2 or square of abs value would represent the power then." this is from textbook for single plane wave only.
The transmission is a normalized transmitted power. Please check this https://optics.ansys.com/hc/en-us/articles/360034405354-transmission-Script-command
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August 23, 2022 at 12:58 am
smzia
SubscriberI have read the link for transmission-script command. T is normalized transmitted power.
There are 7 scalar operation. None, Real, negative Real, Imaginary, Absolute, Absolute_square & Angle.
I need to use one of them to see the transmitted power. if I choose 'None' then there will be no result. I think 'Imaginary' & 'Angle' will not give transmitted power result.
So, which scalar operation should I choose among Real, Negative Real, Absolute & Absolute_square to visulize the transmitted power?
Could you please give any suggestions?
Regards,
Zia
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August 23, 2022 at 2:20 am
Guilin Sun
Ansys EmployeeSo for transmission T, only Real or Abs are good to use. Again, the visualzier is a general tool so its operatons may not be available for different physical quantities.
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August 23, 2022 at 2:53 am
smzia
SubscriberThank you so much Guilin Sun!
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March 11, 2023 at 11:54 pm
gpsar
SubscriberHi smzia,
I am currently trying to figure something out regarding transmission "T" in FDTD and I came upon your discussion here, and I saw that in one of your replies you mentioned that "if T is electic field then, Abs^2(T) will visulaize power transmission. As , P=E^2." Is there any way you could explain to me, or point me in the right direction, as to how P = E^2? This would be of great help to me. Thank you!
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March 13, 2023 at 4:23 pm
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March 13, 2023 at 8:56 pm
gpsar
SubscriberHi Guilin,
Thanks for your reply. In this case though, would P be the Poynting vector? So, does the Poynting vector, P = |E|^2? Would it possible to tell me which book the screenshot is from? Thank you
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March 13, 2023 at 11:35 pm
Guilin Sun
Ansys EmployeeNot realy: the textbook oversimplifies this relation for plane wave only, and it does not depend on space. However, in simultion,the Poynting vectors are a funciton of space, so Px, Py and Pz are power density (Poynting vector), not the power. Power is the integration of P dot source normal over the monitor plane, as show in the link of the first reply: the script command "transmission".
You should be able to find a textbook for such relationship. You can also search online for Optical Intensity.
Please note that in most cases Lumerical's tranmission is always normalized to the source power.
In addition, the forum policy is for "one question one answer" for better reference. So if you have quesitons different from the first post, please write a new post. Thank you!
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June 26, 2023 at 4:57 am
Tisha Elizabeth Tomy
SubscriberHi,
I wanted to ask you how to get the phase of a transmitted light through metasurface?
how to separate the LCP and RCP components of a transmitted light from metasurfce for a LCP or RCP incident?
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June 26, 2023 at 3:50 pm
Guilin Sun
Ansys EmployeePhase is associated with field component or S paramters. So you will need to access field-quantity. In addition, usually phase is a single value. However is can be distribute in space. ONce you define a reference point or a plane, you can use field component to get the phase. Pleae refer to the Metamaterial exmaple https://optics.ansys.com/hc/en-us/articles/360042097393-Metamaterial-parameter-extraction-Smith
You will decompose the fields into LCP and RCP.
Those are not the scope of this post. Please try and in case you cannoy find solutions, please write new posts for each.
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August 26, 2023 at 8:37 pm
Sijing Zhong
SubscriberHi,
I have two input light and I use frequency domain field and power to measure the output. Does the transmission I get equal to the output light intensity over the intensity of two input light?
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August 28, 2023 at 4:18 pm
Guilin Sun
Ansys EmployeeIt is normalized with source power, not intensity.
Please note that if the two sources do not have the signal, or thebandwidth/center wavelegth, the frequency domai normalization can have peoblem in theory. If you have questions regarding to this please write another post.
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- The topic ‘Transmission “T” attribute in Lumerical FDTD’ is closed to new replies.
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