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Static Temperature equal to Wall Temperature?

    • abs95
      Subscriber

      Hello,

      Does the static temperature at a solid-fluid interface wall give the temperature of the solid? Or should I go with the wall temperature to get the solid temperature? Does the adjacent cell zone play a role in this, as Fluent assigns two walls at the interface: one with a adjacent cell zone of fluid and one with adjacent cell zone of solid?

      Thanks!

    • Rob
      Forum Moderator
      It'll give the temperature of the facet, which will be a function of the fluid and solid cell temperatures assuming you've not changed anything on the wall. Wall and wall:shadow are there to give labels to the two sides of the same surface. They're used to allow different roughness settings (for example) on either side.
    • abs95
      Subscriber
      Thank you for your answer. I have this geometry below. I am using this geometry to test my BCs, which I am planning to intruduce to a much more complex geometry. That is why I am also modelling the solid part. For this geometry I have the BCs below.
      I think I get 4 wall conditions to the interface. 2 (wall 12 and wall 13) are assigned to the interface BC extra to the wall 7 and wall 7 shadow. What do all of these walls mean and why are there 4 instead of 2?
    • Amine Ben Hadj Ali
      Ansys Employee
      Interface will create overlapping and overlapping boundaries. The overlapping part are the wall and its shadow. The other ones are related to the non-overlapping. Check the documentation and in Fluent click on the interface in the Mesh Interfaces and hit "list" to list all information / boundaries related to the mesh interface!
    • abs95
      Subscriber
      If I I make the solid and fluid one part in the Design Modeler, I dont have the "interface" (contact region src and contact region trg) and their corresponding walls (wall 12 and wall 13) anymore. In that case I am left with only wall 7 and wall 7 shadow. I wanted to see if these two cases (Case 1: With the "interface" and Case2: without "interface") are equvialent. In the both cases I introduced a heat generation rate of 600000 W/m3 and a wall thickness of 0.001 m to wall 7 (also automatically to wall 7 shadow because they are coupled ). Inlet velocity is 0.02 m/s and temperature of 500K. Outer Walls are all adiabatic. In the case 1 I left wall 12 and 13 as default which is heatflux, thickness and heat generation rate 0. Both cases gave me different results. Below are the temperature contours at the outlet for both cases:
      Case1:
      Case 2:

      My questions are:
      1) Why there is a difference of around 200K? Why are the solutions not identical?
      2) Which solution can I trust? Which approach is more "legit" ?
      3)How can I make the two cases give the same output?


    • Amine Ben Hadj Ali
      Ansys Employee
      If you have multibody part you won't have contact or interfaces.
      Difference might be due to wrong setup and the definition of walls at the interface. For that reason I asked for mesh interface panel and what Fluent prints if you list that interface.

    • abs95
      Subscriber
      I printed the mesh interface before and after initilization. After initilization it tells me one side is "filled" with wall 7 and the other side with wall 7 ratio. Does that mean the solution without walls 12 and 13 is more correct and I should get rid of them by deleting the mesh interface (contact region)?
      Edit: I found out that by deleting the mesh interface I get rid of also the wall 7 and wall 7 shadow. Should I in that case check the "Matching" option at the "Interface Options" ?



    • Amine Ben Hadj Ali
      Ansys Employee
      Matching is not for walls. Rather use the option coupled. But any way the sides are matching. Do both cases converge well? What about the heat flux report at the interfaces and other boundaries?
    • abs95
      Subscriber
      After rerunning it, I realized I posted something wrong for the outlet Temperature for the case 1. Instead of having lower temperatures I have higher temperatures:
      Both cases converge well (continuity, x, y, z velocities, k, omega below 1e-3 energy below 1e-6 )
      For the case 1: I have 0 wall heat flux at all boundaries (including interfaces), which makes sense to me as I set the heat flux on the lateral outer boundary and the outer and the outer "ring walls" next to the inlet and outlet equal to 0.

      However for case 2 (screenshots below): I have non zero heatflux at the rings and therefore (I think) non-zero heat flux at the interface.
      It appears that Fluent did not calculate the equations with rings being adiabatic, although I set the heat flux 0 there as a boundary condition. Why would Fluent in the case 1 implement my boundary condition how I set it and not for the case 2?


    • Amine Ben Hadj Ali
      Ansys Employee
      Please do the Flux Report in Fluent and not in CFD-Post.
    • abs95
      Subscriber
      For the case 1: I have 0 W at the all outer boundary (rings and lateral) and contact region trg and src and wall 12 13, 0.00729 W at wall 7 , 565.453 W at the wall 7:shadow
      For the case 2: again 0 W at the all outer boundary (rings and lateral), 161.860 W at wall 7, 403.605 W at wall 7 shadow
    • Amine Ben Hadj Ali
      Ansys Employee
      Both cases showing strange behavior. Focus on the case with no interfaces and try to understand why the flux at one side of the wall does not match the flux on the other side of wall.
    • abs95
      Subscriber
      Could it be because how I implemented the heat generation rate and the wall thickness? What I am trying to implement in the end is a surface heat source at the wall which will eventually heat up the adjacent solid and fluid. (I know the cases I show does not heat up the solid because I set the outer walls to be adiabatic but eventually I will set a convection BC there after solving these issues) . As setting a surface heat source was not possible, I had to go with the option of putting a small thickness and giving the equivalent volumetric heat source.


    • Rob
      Forum Moderator
      If the solid is surrounded by adiabatic walls it makes sense that more heat is added to the fluid: it's going to be cooler. If you check the heat you add into the wall against the inlet & outlet how does it tie up?
    • Amine Ben Hadj Ali
      Ansys Employee
      You then should get the net impact of that as you know the thickness and the area of the walls.
    • abs95
      Subscriber
      What do you mean with heat added into the wall against the inlet & outlet? How do I check it?
      Yes the heat added by the source is 565.488 W. The net heat between the walls for the cases 1 and 2 are 565.461 W and 565.4656 W respectively, which are almost the same as the original inputted heat source. Why would however heat fluxes at the walls be different for two cases?

    • Rob
      Forum Moderator
      Use the Flux Reports, tag inlet and outlet and look at the difference. That should equal the amount added through the wall.
      If you're comparing 565.461 with 565.4656 you're looking at a variation of approximately 0.0001%. Given it's an iterative solver I'd be fairly confident in saying the difference is due to convergence and rounding error. Remember we're dealing with engineering numbers, so don't expect agreement to 19 significant figures.
    • Amine Ben Hadj Ali
      Ansys Employee
      Difference is not high and acceptable.
    • abs95
      Subscriber
      With the different heat fluxes at the walls I actually meant this:
      For the case 1 with the "interfaces" the wall and wall shadow have 0.00729 W and 565.453 W respectively.
      For the case 2 without the "interfaces" the wall and wall shadow have 161.860 W and 403.605W respectively.
      My question was actually: Although the net heat at the wall and wall shadow is the same for both cases why are the individual fluxes at the wall and wall shadow very different between two cases? Sorry I should have formulated my question more clearly.
      The net heat through inlet and outlet for case 1 and case 2 is -456.2869 W and -246.943 W respectively, so they are no equal to the heat added through the wall.

    • Amine Ben Hadj Ali
      Ansys Employee
      Okay: that is weird and for that reason I was asking how you defined the interfaces: manually or automatically generated. From your interface screenshots in the top: the interfaces are matching and 100% overlapping. I recommend that you test one run with Coupled Mesh Interface.
    • abs95
      Subscriber
      The interfaces were automatically generated. I ran with "Coupled Walls" option. The results are the same.
    • Amine Ben Hadj Ali
      Ansys Employee
      If both cases are converging and monitor points are not varying I am expecting that both result should be same with slight differences assuming now your setup at the interface is correct and all other settings and conditions are same.
      What you can do is the following: start from wall wall shado cars (no nci) slit the wall change them to interfaces and create a new interface connection and run.
    • Rob
      Forum Moderator
      For info, the slit command is in the TUI under mesh/modify-zones
    • abs95
      Subscriber
      It worked out, they match if I do like that! Thank you very much!
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