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NON LINEAR BUCKLING ANALYSIS H BEAM

    • Shahrukh Ahmed
      Subscriber

      Hi everyone,

      I am trying to perform non linear buckling analysis in ANSYS Mechanical APDL 2021 R1.

      But the bending stress capacity i am getting (product of reduction factor and yield stress) theoretically is nowhere matching with the numerical results.

      fbd(reduction factor x yield stress(250MPa) = 201.2 MPa
      fbd(as per model) = 21MPa


      Here is my code 


      blen=10.0
      depth=0.55
      fwidth=0.210
       
      fthk=17.2/1000
      wthk=11.1/1000
       
       
       
      TAREA,0,0,0,depth/2.0,0,blen,1
      TAREA,0,0,depth/2.0,depth,0,blen,1
      TAREA,-fwidth/2.0,0.0,0,0,0,blen,2
      TAREA,-fwidth/2.,0,depth,depth,0,blen,2
      TAREA,0,fwidth/2.0,0,0,0,blen,2
      TAREA,0,fwidth/2.0,depth,depth,0,blen,2
      !TACUT,0,0,0,depth,0,blen,0.3
       
      poi=0.3
       
      damp1=0.02
      !Material Number 1
      ex,  1,      2e5*1000
      ey,  1,      2e5*1000
      nuxy,1,      poi
      gxy, 1,      2e5*1000/(2*(1+poi))
      dens,1,      2.5
      alpx,1,      9.50E-06
      alpy,1,      9.50E-06
      damp,1,      damp1
       
      ET,  11,  shell181 !Wall
       
      SECTYPE,111,SHELL
      SECDATA,fthk,
       
      SECTYPE,112,SHELL
      SECDATA,wthk,
       
      TASEL,0,0,0,depth,0,blen,1
      AATT,1,,11,,112
       
       
      TASEL,-fwidth/2.0,fwidth/2.0,0,0,0,blen,2
      AATT,1,,11,,111
       
      TASEL,-fwidth/2.,fwidth/2.0,depth,depth,0,blen,2
      AATT,1,,11,,111
       
      allsel,all
       
      aclear,all
      esize,0.1
      amesh,all,all
       
       
      ddele,all,all
      tnsel,0,0,depth/2,depth/2,0,0,
      d,all,uy,0
      d,all,rotz,0
       
      tnsel,0,0,depth/2,depth/2,blen,blen,
      d,all,uy,0
      d,all,uz,0
      d,all,rotz,0
       
       
      tnsel,0,0,0,depth,0,0,0,
      d,all,ux,0
       
      tnsel,0,0,0,depth,blen,blen,
      d,all,ux,0
       
      !LeftSides
       
      fdele,all,all
      logforce=1/(0.5328*2)
       
      tnsel,-fwidth/2,-fwidth/2,0,0,0,0,0,
      f,all,fz,-logforce
       
      tnsel,-fwidth/2,-fwidth/2,depth,depth,0,0,0,
      f,all,fz,logforce
       
      tnsel,fwidth/2,fwidth/2,0,0,0,0,0,
      f,all,fz,-logforce
       
      tnsel,fwidth/2,fwidth/2,depth,depth,0,0,0,
      f,all,fz,logforce
       
       
      tnsel,-fwidth/2,-fwidth/2,0,0,blen,blen
      f,all,fz,logforce
       
      tnsel,-fwidth/2,-fwidth/2,depth,depth,blen,blen
      f,all,fz,-logforce
       
      tnsel,fwidth/2,fwidth/2,0,0,blen,blen
      f,all,fz,logforce
       
      tnsel,fwidth/2,fwidth/2,depth,depth,blen,blen
      f,all,fz,-logforce
       
       
      allsel,all  
      eplot   
       
      !*change material
       
      /VIEW,1,1,1,1   
      /ANG,1  
      /REP,FAST   
      /DIST, 1 ,1.082226,1
      /REP,FAST   
      /DIST, 1 ,1.082226,1
      /REP,FAST   
      /DIST, 1 ,1.082226,1
      /REP,FAST   
      /DIST, 1 ,1.082226,1
      /REP,FAST   
      /DIST, 1 ,1.082226,1
      /REP,FAST   
      FINISH  
      /SOL
      FINISH  
      /PREP7  
      !*  
      TB,BISO,1,1,2,  
      TBTEMP,0
      TBDATA,,250000,0,,,,
       
       
       
       
      !*static anlaysis 
       
       
      /VIEW,1,1,1,1   
      /ANG,1  
      /REP,FAST   
      FINISH  
      /SOL
      PSTRES,1
      !*  
      ANTYPE,0
      solve   
      !*  
      !*  
      !*  
      !*  
      !*  
      !*  
      FINISH  
       
      !* eigenvalue buckling analysis
      /SOLUTION   
      ANTYPE,1
      !*  
      FINISH  
      /POST1  
      FINISH  
      /PREP7  
      FINISH  
      /SOL
      !*  
      BUCOPT,LANB,10,0,0,CENTER   
      solve   
      FINISH  
      /POST1  
      !*  
      /EFACET,1   
      PLNSOL, U,SUM, 0,1.0
      SET,LIST,999
      )/GOP     
       
      !*********************************************UPGEOM
      allsel,all
      eplot
      /PREP7  
      UPGEOM,10/350,1,6,'test','rst',' '  
      FINISH  
      /SOL
       
      eplot
       
      !*change force
      fdele,all,all
      logforce=1000/(0.5328*2)
       
      tnsel,-fwidth/2,-fwidth/2,0,0,0,0,0,
      f,all,fz,-logforce
       
      tnsel,-fwidth/2,-fwidth/2,depth,depth,0,0,0,
      f,all,fz,logforce
       
      tnsel,fwidth/2,fwidth/2,0,0,0,0,0,
      f,all,fz,-logforce
       
      tnsel,fwidth/2,fwidth/2,depth,depth,0,0,0,
      f,all,fz,logforce
       
       
      tnsel,-fwidth/2,-fwidth/2,0,0,blen,blen
      f,all,fz,logforce
       
      tnsel,-fwidth/2,-fwidth/2,depth,depth,blen,blen
      f,all,fz,-logforce
       
      tnsel,fwidth/2,fwidth/2,0,0,blen,blen
      f,all,fz,logforce
       
      tnsel,fwidth/2,fwidth/2,depth,depth,blen,blen
      f,all,fz,-logforce
       
      allsel,all
      eplot
       
      !*NLGEOM
       
      !*  
      ANTYPE,0
      ANTYPE,0
      NLGEOM,1
      NSUBST,100,100,1
      OUTRES,ERASE
      OUTRES,ALL,ALL  
      RESCONTRL,DEFINE,ALL,ALL,-1 
      TIME,1  
      FINISH  
      /POST1  
      FINISH  
      /SOL
      !*  
      !*  
      NLGEOM,1
      NROPT,AUTO, ,OFF
      LUMPM,0 
      EQSLV, , ,0, ,DELE  
      MSAVE,0 
      PCGOPT,0, ,AUTO, , ,AUTO
      PIVCHECK,0  
      PSTRESS,0   
      TOFFST,0,   
      !*  
      solve   
       
      eplot




      What is wrong with my analysis ??

    • dlooman
      Ansys Employee

      The APDL Materials Reference gives the example input below for temp-dependent bilinear isotropic hardening.  You appear to have only specified the yield stress.  Perhaps a shell element isn't the best choice for a plasticity analysis.  Perhaps a thin solid with several elements through the thickness would be more accurate.   

      /prep7
      MPTEMP,1,0,500            ! Define temperatures for Young's modulus
      MPDATA,EX,1,,14E6,12e6           
      MPDATA,PRXY,1,,0.3,0.3
      TB,PLAS,1,2,,BISO         ! Activate a data table
      TBTEMP,0.0                ! Temperature = 0.0
      TBDATA,1,44E3,1.2E6       ! Yield = 44,000; Plastic Tangent modulus = 1.2E6
      TBTEMP,500                ! Temperature = 500
      TBDATA,1,29.33E3,0.8E6    ! Yield = 29,330; Plastic Tangent modulus = 0.8E6    
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