Learning Forum

[guillaume.renedo]

Hello everyone,

I am using LS-DYNA ICFD for hemodynamic simulations.

I would like to implement a purely resistive outlet boundary condition (i.e., only R2, with R1 = C1 = L1 = 0). However, the solver diverges when I set C1 = 0 (division by 0 not allowed)

Is there a way to define a purely resistive model at the outlets using the available WTYPE circuit options in the card?

If not, could you clarify how WTYPE = 6 works, particularly regarding the use of the "icfd_usercircuit" in the file dyn21icfd.f?

Thank you in advance for your help.

Best regards,
Gred

[ErKo]

 

 

 

 

 

Hello

As you say it divides by zero so not good to set C1=0 – but it should perhaps remove it from equations – will get back on that.

Or perhaps try this  just use R1 and C1>>>0 (very large comapred to Q), and L1=0. We get then :

Q=P/R2 which is like pure resistance. But might not be the best as it might introduce issues.

Try it out and let us know if you get this res. beh.

 

Thank you

Erko

 

 

 

 

 

 

[ErKo]

Hi

I saw that a support ticket was created for this so we will continue helping you there (via Channel Partner).

Closing here.
All the best
Erko