Learning Forum

[AntoineRo]

Hi there !

I was wondering if there was an easy way to plot the maximal absolute principal stress on ANSYS Workbench. 

The following "User-defined Result" allows to do so but I would like to keep the negative signs for compression and the positive signs for tension. 

Is there a way without using APDL since I have never used it please ?

I guess it should look something like this :

IF(abs(S1)>abs(S3) ; S1 ; S3)

But there seems to be a syntax error. 

 

Thanks a lot !

Regards,

Antoine 

[Sai Deogekar]

Hi!

The IF statement cannot be used in User-Defined Results. You may go through the following Documentation:

https://ansyshelp.ansys.com/account/secured?returnurl=/Views/Secured/corp/v201/en/wb_sim/ds_user_defined_express.html

 

One was to get around it would be to use APDL commands in Mechanical. To do this, right-click on Solution-->Insert-->Commands. In the Commands window, paste the following:

/graphics,power

 

set,1,last           !Choose the last substep in step 1

 

!Define the RGB colors

/RGB,INDEX,100,100,100,0

/RGB,INDEX,80,80,80,13

/RGB,INDEX,60,60,60,14

/RGB,INDEX,0,0,0,15

/TRIAD,off

 

*IF,S1,ABGT,S3,THEN        !Similar to IF(abs(S1)>abs(S3))

/SHOW,PNG                       ! This will save a png file in projectname_files/dp0/SYS/MECH

/view,1,1,1,1                        ! Set the view angle

ESEL,all

PLNSOL,S,1

*ELSE

/SHOW,PNG

/view,1,1,1,1

ESEL, all

PLESOL,S,3

 

Hope this helps,

Sai

[AntoineRo]

Hello Sai,

Thanks a lot for your quick answer !

Your solution seems to work even though I am wondering if the "if" condition applies to each element or to the total assembly. 

Unfortunatly for this project, I don't have much time to look into the APDL coding to find the correct view I need. 

I will stick to using 2 different plots on Mechanical for now. 

Thanks again for your time and answer, 

Regards, 

Antoine 

 

[Philipp Holzmann]

Hello.

I am late with my answer, but I would still like to show a simple solution to the problem.

 - User defined Result with the following expression:

The first term gives the positive or negative sign, the second term is the same as you already suggested.

 

Hope this helps,

Philipp

[ErKo]

 

Hi

Thank you.

As this post is very old, we are closing it (perhaps users will find the solution useful).