Learning Forum

[Govindp0037]

I am validating paper : Numerical modelling of the temperature distribution in a two-phase closed thermosyphon

As heat input value is given in paper. But during simulation in boundary condition we have to apply heat flux. So in 2D model of thermosyphon how to calculate heat flux value for particular heat input and how to give boundary condition on two vertical wall of evaporator...

Same as how to apply heat transfer coefficient to the two wall of condenser of 2d thermosyphon in boundary conditions... Should i apply differently for each wall or make it combine two wall as condenser wall and apply heat transfer coefficient

[Rob]

Have a look at the various options for external wall boundaries. The heat flux will put in a set amount of energy, a convection boundary allows the setting of the far field temperature and EXTERNAL heat transfer coefficient. 

[Govindp0037]

That's i knw but in paper heat input in Watt is given and for 2d simulation of thermosyphon to calculate heat flux (Watt/m2) , as area what should i taken? Should i take (2*3.14*r*length of evaporator) or only simple (2*length of evaporator) I tried by taking the (2*3.14*r*length of evaporator) as area to calculate heat flux.. But after simulation completed, my evaporator temp and condenser temp comming same...

[Rob]

If you're in 2d the domain is 1m thick (for the purposes of working out an area). For 2d-axi I think it's Pi radians, but best approach is to use the Report tools and do the sums. 

[Govindp0037]

Actually i dont get it as you said to use report tools.

[Rob]

Yes, under "Results".

[Govindp0037]

I m not getting wt u r trying to say.. Can u elaborate it?

[Rob]

You were asking about wall area: that is available in the Report tools in Fluent. 

[SRICHARAN285]

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HI

i am also doing on 2d heat pipe

are you done this.?

.

[SRICHARAN2897]

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hi govindp

did you completed your project on heat pipe

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