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April 2, 2024 at 7:35 pm
Shahrukh Ahmed
SubscriberHi everyone,
I am trying to perform non linear buckling analysis in ANSYS Mechanical APDL 2021 R1.
But the bending stress capacity i am getting (product of reduction factor and yield stress) theoretically is nowhere matching with the numerical results.
fbd(reduction factor x yield stress(250MPa) = 201.2 MPa
fbd(as per model) = 21MPa
Here is my codeblen=10.0depth=0.55fwidth=0.210fthk=17.2/1000wthk=11.1/1000TAREA,0,0,0,depth/2.0,0,blen,1TAREA,0,0,depth/2.0,depth,0,blen,1TAREA,-fwidth/2.0,0.0,0,0,0,blen,2TAREA,-fwidth/2.,0,depth,depth,0,blen,2TAREA,0,fwidth/2.0,0,0,0,blen,2TAREA,0,fwidth/2.0,depth,depth,0,blen,2!TACUT,0,0,0,depth,0,blen,0.3poi=0.3damp1=0.02!Material Number 1ex, 1, 2e5*1000ey, 1, 2e5*1000nuxy,1, poigxy, 1, 2e5*1000/(2*(1+poi))dens,1, 2.5alpx,1, 9.50E-06alpy,1, 9.50E-06damp,1, damp1ET, 11, shell181 !WallSECTYPE,111,SHELLSECDATA,fthk,SECTYPE,112,SHELLSECDATA,wthk,TASEL,0,0,0,depth,0,blen,1AATT,1,,11,,112TASEL,-fwidth/2.0,fwidth/2.0,0,0,0,blen,2AATT,1,,11,,111TASEL,-fwidth/2.,fwidth/2.0,depth,depth,0,blen,2AATT,1,,11,,111allsel,allaclear,allesize,0.1amesh,all,allddele,all,alltnsel,0,0,depth/2,depth/2,0,0,d,all,uy,0d,all,rotz,0tnsel,0,0,depth/2,depth/2,blen,blen,d,all,uy,0d,all,uz,0d,all,rotz,0tnsel,0,0,0,depth,0,0,0,d,all,ux,0tnsel,0,0,0,depth,blen,blen,d,all,ux,0!LeftSidesfdele,all,alllogforce=1/(0.5328*2)tnsel,-fwidth/2,-fwidth/2,0,0,0,0,0,f,all,fz,-logforcetnsel,-fwidth/2,-fwidth/2,depth,depth,0,0,0,f,all,fz,logforcetnsel,fwidth/2,fwidth/2,0,0,0,0,0,f,all,fz,-logforcetnsel,fwidth/2,fwidth/2,depth,depth,0,0,0,f,all,fz,logforcetnsel,-fwidth/2,-fwidth/2,0,0,blen,blenf,all,fz,logforcetnsel,-fwidth/2,-fwidth/2,depth,depth,blen,blenf,all,fz,-logforcetnsel,fwidth/2,fwidth/2,0,0,blen,blenf,all,fz,logforcetnsel,fwidth/2,fwidth/2,depth,depth,blen,blenf,all,fz,-logforceallsel,alleplot!*change material/VIEW,1,1,1,1/ANG,1/REP,FAST/DIST, 1 ,1.082226,1/REP,FAST/DIST, 1 ,1.082226,1/REP,FAST/DIST, 1 ,1.082226,1/REP,FAST/DIST, 1 ,1.082226,1/REP,FAST/DIST, 1 ,1.082226,1/REP,FASTFINISH/SOLFINISH/PREP7!*TB,BISO,1,1,2,TBTEMP,0TBDATA,,250000,0,,,,!*static anlaysis/VIEW,1,1,1,1/ANG,1/REP,FASTFINISH/SOLPSTRES,1!*ANTYPE,0solve!*!*!*!*!*!*FINISH!* eigenvalue buckling analysis/SOLUTIONANTYPE,1!*FINISH/POST1FINISH/PREP7FINISH/SOL!*BUCOPT,LANB,10,0,0,CENTERsolveFINISH/POST1!*/EFACET,1PLNSOL, U,SUM, 0,1.0SET,LIST,999)/GOP!*********************************************UPGEOMallsel,alleplot/PREP7UPGEOM,10/350,1,6,'test','rst',' 'FINISH/SOLeplot!*change forcefdele,all,alllogforce=1000/(0.5328*2)tnsel,-fwidth/2,-fwidth/2,0,0,0,0,0,f,all,fz,-logforcetnsel,-fwidth/2,-fwidth/2,depth,depth,0,0,0,f,all,fz,logforcetnsel,fwidth/2,fwidth/2,0,0,0,0,0,f,all,fz,-logforcetnsel,fwidth/2,fwidth/2,depth,depth,0,0,0,f,all,fz,logforcetnsel,-fwidth/2,-fwidth/2,0,0,blen,blenf,all,fz,logforcetnsel,-fwidth/2,-fwidth/2,depth,depth,blen,blenf,all,fz,-logforcetnsel,fwidth/2,fwidth/2,0,0,blen,blenf,all,fz,logforcetnsel,fwidth/2,fwidth/2,depth,depth,blen,blenf,all,fz,-logforceallsel,alleplot!*NLGEOM!*ANTYPE,0ANTYPE,0NLGEOM,1NSUBST,100,100,1OUTRES,ERASEOUTRES,ALL,ALLRESCONTRL,DEFINE,ALL,ALL,-1TIME,1FINISH/POST1FINISH/SOL!*!*NLGEOM,1NROPT,AUTO, ,OFFLUMPM,0EQSLV, , ,0, ,DELEMSAVE,0PCGOPT,0, ,AUTO, , ,AUTOPIVCHECK,0PSTRESS,0TOFFST,0,!*solveeplot
What is wrong with my analysis ?? -
April 3, 2024 at 5:29 pm
dlooman
Ansys EmployeeThe APDL Materials Reference gives the example input below for temp-dependent bilinear isotropic hardening. You appear to have only specified the yield stress. Perhaps a shell element isn't the best choice for a plasticity analysis. Perhaps a thin solid with several elements through the thickness would be more accurate.
/prep7 MPTEMP,1,0,500 ! Define temperatures for Young's modulus MPDATA,EX,1,,14E6,12e6 MPDATA,PRXY,1,,0.3,0.3 TB,PLAS,1,2,,BISO ! Activate a data table TBTEMP,0.0 ! Temperature = 0.0 TBDATA,1,44E3,1.2E6 ! Yield = 44,000; Plastic Tangent modulus = 1.2E6 TBTEMP,500 ! Temperature = 500 TBDATA,1,29.33E3,0.8E6 ! Yield = 29,330; Plastic Tangent modulus = 0.8E6
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