Reply To: CHARGE – Creating SiO2 Semiconductor

[sicli21]

Thank you for your response. In https://optics.ansys.com/hc/en-us/articles/360042326694-Ferroelectric-modulator , it says 

 

"""

Due to the same reason as the one mentioned above, the Si layer in the waveguide also requires a voltage boundary condition. Instead of providing the boundary condition directly from a contact (gnd) we provided the boundary condition through another semiconductor region

"""

 

If I make my SiO2 insulator, my semiconductor waveguide won't have any BC and according to the example that may cause inaccurate results.