Torsion of Box and Open Sections — Lesson 5

This lesson covers the concept of torsion in segmented box sections. It explains the formula derived for torsion and illustrates it with an example. The lesson further discusses the application of the formula in different scenarios, including the calculation of flows in different cells. It also explains the relationship between different flows and how they are related to equilibrium. The lesson concludes with the application of the membrane analogy for thin box sections and open sections, and how to calculate the maximum shear stress in different cases.

Video Highlights

01:11 - Explanation of the problem with a segmented section and the thickness of the wall.
06:11 - Explanation of the relationship between the flows and the angle of twist per unit length.
12:41 - Explanation of the membrane analogy for thin box sections.
19:59 - Explanation of the membrane analogy for thin open sections
22:37 - Explanation of the maximum shear stress and the torque capacity for different open sections.
24:39 - Explanation of the maximum shear stress and the torque capacity for different closed sections
32:40 - Explanation of the maximum shear stress and the torque capacity for different thin rectangular sections.
45:22 - Explanation of the maximum shear stress and the torque capacity for different thin circular sections.
49:14 - Explanation of the stiffness of the two sections and the maximum stresses.

Key Takeaways

- The formula for torsion in segmented box sections can be applied to calculate flows in different cells.
- The flows in different cells are related and can be understood through the concept of equilibrium.
- The membrane analogy can be applied to thin box sections and open sections to understand the behavior of these sections under torsion.
- The maximum shear stress in different cases can be calculated using the derived formulas.