{"id":369803,"date":"2024-06-04T15:19:33","date_gmt":"2024-06-04T15:19:33","guid":{"rendered":"\/forum\/forums\/topic\/mirror-impedance-capacitance-between-two-bodies\/"},"modified":"2024-06-04T15:19:33","modified_gmt":"2024-06-04T15:19:33","slug":"mirror-impedance-capacitance-between-two-bodies","status":"closed","type":"topic","link":"https:\/\/innovationspace.ansys.com\/forum\/forums\/topic\/mirror-impedance-capacitance-between-two-bodies\/","title":{"rendered":"Mirror impedance &#8211; capacitance between two bodies"},"content":{"rendered":"<p>I am trying to obtain the input impedance (reactance) between a mirror and its housing. The mirror is insulated from the housing (which is grounded) by some dielectrics. To simplify, the dielectrics were removed from the model. So I have a body (mirror) and a gap of 1 mm to its housing. Both bodies are &nbsp;enclosed in a parallelepiped with ???????? = 1, which performs the function of the environment. The &ldquo;perfect electric conductor&rdquo; (PEC) boundary conditions was assigned to the exterior walls of this structure. I introduced a port between the housing and body by means of a coaxial.&nbsp; Electromagnetic RF excitation is applied to the coaxial port located on the reverse side of the mirror. I simulated the model in HFSS for f=80 MHz using a lumped port. Then, I calculated the impedance of the mirror to the housing with the S-parameters: Im(????????) = Im(50(1 + S11\/(1 &minus; S11))), where S11 is the EM voltage wave reflection coefficient and 50 is the characteristic impedance. The result is ~j1 &Omega;. However, if I calculate the reactance theoretically, it results in ~2.6 &Omega;. The theoretical value was calculated considering ????=(&epsilon;&middot;????)\/???? and <!-- [if gte msEquation 12]&gt;--><span style='font-size:14.0pt;font-family:\"Cambria Math\";color:black;font-weight:normal;font-style:italic'><\/span><span style='font-size:14.0pt;font-family:\"Cambria Math\";color:black;font-weight:normal;font-style:italic'>&#119885;<\/span><span style='font-size:14.0pt;font-family:\"Cambria Math\";color:black;font-weight:normal;font-style:italic'>&#119861;<\/span><span style='font-size:14.0pt;font-family:\"Cambria Math\";color:black;font-weight:normal;font-style:italic'>=<\/span><span style='font-size:14.0pt;font-family:\"Cambria Math\";color:black;font-weight:normal;font-style:italic'><\/span><span style='font-size:14.0pt;font-family:\"Cambria Math\";color:black;font-weight:normal;font-style:italic'>&#119883;<\/span><span style='font-size:14.0pt;font-family:\"Cambria Math\";color:black;font-weight:normal;font-style:italic'>&#119862;<\/span><span style='font-size:14.0pt;font-family:\"Cambria Math\";color:black;font-weight:normal;font-style:italic'>=<\/span><span style='font-size:14.0pt;font-family:\"Cambria Math\";color:black;font-weight:normal;font-style:italic'><\/span><span style='font-size:14.0pt;font-family:\"Cambria Math\";color:black;font-weight:normal;font-style:italic'>1<\/span><span style='font-size:14.0pt;font-family:\"Cambria Math\";color:black;font-weight:normal;font-style:italic'>&#119895;<\/span><span style='font-size:14.0pt;font-family:\"Cambria Math\";color:black;font-weight:normal;font-style:italic'>2<\/span><span style='font-size:14.0pt;font-family:\"Cambria Math\";color:black;font-weight:normal;font-style:italic'>&#120587;<\/span><span style='font-size:14.0pt;font-family:\"Cambria Math\";color:black;font-weight:normal;font-style:italic'>&#119891;&#119862;<\/span><!-- [if !msEquation]-->Z_B=X_C=1\/j2&pi;fC, where A=area=86834.78 mm2 and S=separation=1 mm. &epsilon;=1 since the bodies are separated with vacuum. Is this method correct to obtain the reactance\/capacitance between two bodies?&nbsp;<\/p>\n","protected":false},"template":"","class_list":["post-369803","topic","type-topic","status-closed","hentry","topic-tag-capacitance","topic-tag-hfss","topic-tag-Impedancecalculation-1"],"aioseo_notices":[],"aioseo_head":"\n\t\t<!-- All in One SEO 4.9.10 - aioseo.com -->\n\t<meta name=\"description\" content=\"I am trying to obtain the input impedance (reactance) between a mirror and its housing. The mirror is insulated from the housing (which is grounded) by some dielectrics. To simplify, the dielectrics were removed from the model. So I have a body (mirror) and a gap of 1 mm to its housing. 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