{"id":363323,"date":"2024-04-20T20:42:22","date_gmt":"2024-04-20T20:42:22","guid":{"rendered":"\/forum\/?post_type=topic&p=363323"},"modified":"2024-04-22T14:52:47","modified_gmt":"2024-04-22T14:52:47","slug":"withdraw-test","status":"closed","type":"topic","link":"https:\/\/innovationspace.ansys.com\/forum\/forums\/topic\/withdraw-test\/","title":{"rendered":"Withdraw test"},"content":{"rendered":"

Hi,<\/p>\n

I am trying to make a simulation to match the experimental result with some data from another program<\/p>\n

<\/a><\/p>\n

This is my model, a 4.5 × 50 mm screw (modelled as smooth surface) inserted into a predrilled orthotropic block is the hole diameter slightly smaller than the screw’s diameter (overlapping diameter from another program’s data is 1mm) to create the friction contract (the blue part is the surface of the hole, the red part is the surface of the screw).<\/p>\n

The table is the orthotropic block material:<\/p>\n\n\n\n\n\n\n\n\n\n\n\n\n
\n

Density (kg\/m3)<\/sup><\/span><\/p>\n<\/td>\n

\n

500<\/span><\/p>\n<\/td>\n<\/tr>\n

\n

Young’s Modulus X direction<\/span> (MPa)<\/span><\/span><\/p>\n<\/td>\n

\n

14700<\/span><\/p>\n<\/td>\n<\/tr>\n

\n

Young’s Modulus Y direction<\/span> (MPa)<\/span><\/span><\/p>\n<\/td>\n

\n

737<\/span><\/p>\n<\/td>\n<\/tr>\n

\n

Young’s Modulus Z direction<\/span> (MPa)<\/span><\/span><\/p>\n<\/td>\n

\n

1000<\/span><\/p>\n<\/td>\n<\/tr>\n

\n

Poisson’s Ratio XY<\/span><\/p>\n<\/td>\n

\n

0.449<\/span><\/p>\n<\/td>\n<\/tr>\n

\n

Poisson’s Ratio YZ<\/span><\/p>\n<\/td>\n

\n

0.292<\/span><\/p>\n<\/td>\n<\/tr>\n

\n

Poisson’s Ratio XZ<\/span><\/p>\n<\/td>\n

\n

0.374<\/span><\/p>\n<\/td>\n<\/tr>\n

\n

Shear Modulus XY<\/span> (MPa)<\/span><\/span><\/p>\n<\/td>\n

\n

1150<\/span><\/p>\n<\/td>\n<\/tr>\n

\n

Shear Modulus YZ<\/span> (MPa)<\/span><\/span><\/p>\n<\/td>\n

\n

942<\/span><\/p>\n<\/td>\n<\/tr>\n

\n

Shear Modulus XZ<\/span> (MPa)<\/span><\/span><\/p>\n<\/td>\n

\n

103<\/span><\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

The following are the screw material changed properties, other properties remain unchanged of the default structure steel material<\/span><\/p>\n\n\n\n\n\n\n\n
\n

Density (kg\/m3)<\/sup><\/span><\/p>\n<\/td>\n

\n

8000 <\/span><\/p>\n<\/td>\n<\/tr>\n

\n

Young’s Modulus<\/span> (MPa)<\/span><\/span><\/p>\n<\/td>\n

\n

200000<\/span><\/p>\n<\/td>\n<\/tr>\n

\n

Yield strength<\/span> (MPa)<\/span><\/span><\/p>\n<\/td>\n

\n

215<\/span><\/p>\n<\/td>\n<\/tr>\n

\n

Ultimate strength<\/span> (MPa)<\/span><\/span><\/p>\n<\/td>\n

\n

450<\/span><\/p>\n<\/td>\n<\/tr>\n

\n

Poisson’s Ratio<\/span><\/p>\n<\/td>\n

\n

0.29<\/span><\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

The graph of force reaction for the displacement vs the displacement is plotted to do the comparison. <\/p>\n

<\/a><\/p>\n

the frictional contact is set as mu = 0.3 and with the command<\/p>\n

et ,cid, 174
RMODIF,cid,21, 5.3
RMODIF,cid,22, 4<\/pre>\n
but I am encountering some problems:<\/p>\n
    \n
  1. I wonder why the simulation failed to run the overlapping diameter is 1mm.<\/li>\n<\/ol>\n
    When I set the hole diameter is 3.5mm (overlapping diameter is 1mm), the simulation goes error and gives me these messages. Why would this happen?<\/p>\n
    <\/a><\/p>\n
    2.  The DC coefficient failed to function or function weirdly<\/p>\n
    So as the 1mm overlapping diameter can’t work, I changed the overlapping diameter to a smaller value. but the DC coefficient would either cause errors like that shown in the previous image or give out a strange result that does not decay exponentially. What do I miss for the dynamic friction formula to work properly?<\/p>\n
    <\/a><\/p>\n
    3. How to insert the Hashin failure criterion into the model?<\/p>\n
    I have checked this post (\/forum\/forums\/topic\/hashin-failure-results\/) and the guide but I am still confused about where and how to input the Hashin failure criterion into the material. These are the data I have for the Hashin failure criterion<\/p>\n
    Failure criteria: 
    <\/span>Parallel tension = 108 MPa<\/span>
    Parallel compression = 29.8 MPa<\/span>
    Matrix tension = 2.3 MPa<\/span>
    Matrix compression = 5.5 MPa<\/span>
    Longitudinal shear = 7.8 MPa<\/span>
    Transverse shear  = 7.8 MPa<\/span>
    Fracture energy 
    Longitudinal tension = 1.6 N\/mm
    Longitudinal compression = 60 N\/mm
    Transverse tension = 0.06 N\/mm
    Transverse compression = 0.2 N\/mm<\/p>\n
    <\/span><\/p>\n
    Thanks<\/p>\n
     <\/p>\n
     <\/p>\n
     <\/p>\n
     <\/p>\n","protected":false},"template":"","class_list":["post-363323","topic","type-topic","status-closed","hentry","topic-tag-bolt-modelling-1","topic-tag-error","topic-tag-experimental-data-1","topic-tag-experimental-results-1","topic-tag-failure-criteria","topic-tag-friction-coefficient","topic-tag-mechanical","topic-tag-modelling","topic-tag-result-validation"],"aioseo_notices":[],"aioseo_head":"\n\t\t\n\t\n\t\n\t\n\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t