Hi everyone,<\/p>\n
<\/p>\n
I am doing my M.tech thesis. <\/p>\n
<\/p>\n
I am using ansys workbench to model masonry prism. I need to get the crack pattern So i used SOLID 65 element as command. But it didn’t work. can anyone help me in solving this. The command i used is attached with this.<\/p>\n
<\/p>\n
Please help me. I’m new to this software.<\/p>\n
<\/p>\n
! Properties of masonry<\/p>\n
<\/p>\n
ET,1,SOLID65<\/p>\n
<\/p>\n
R,1,0,0,0,0,0,0<\/p>\n
<\/p>\n
RMORE,0,0,0,0,0<\/p>\n
<\/p>\n
<\/p>\n
<\/p>\n
MP,EX,1,14538.46154<\/p>\n
<\/p>\n
MP,PRXY,1,0.18<\/p>\n
<\/p>\n
MPTEMP,1,0<\/p>\n
<\/p>\n
<\/p>\n
<\/p>\n
TB,CONCR,1,1,9<\/p>\n
<\/p>\n
TBTEMP,22<\/p>\n
<\/p>\n
TBDATA,1,0.2,0.5,0.71,7.88<\/p>\n
<\/p>\n
! Shear transfer coefficients for an open crack. <\/p>\n
<\/p>\n
! Shear transfer coefficients for a closed crack. <\/p>\n
<\/p>\n
!Uniaxial tensile cracking stress.<\/p>\n
<\/p>\n
!Uniaxial crushing stress (positive). <\/p>\n
<\/p>\n
<\/p>\n
<\/p>\n
TB,MISO,1,1,9,0<\/p>\n
<\/p>\n
TBTEMP,22<\/p>\n
<\/p>\n
TBPT,,0.00013,1.89<\/p>\n
<\/p>\n
TBPT,,0.000154,2.10<\/p>\n
<\/p>\n
TBPT,,0.000185,2.50<\/p>\n
<\/p>\n
TBPT,,0.000271,3.21<\/p>\n
<\/p>\n
TBPT,,0.000381,4<\/p>\n
<\/p>\n
TBPT,,0.000491,4.53<\/p>\n
<\/p>\n
TBPT,,0.000578,4.90<\/p>\n
<\/p>\n
TBPT,,0.000811,5.70<\/p>\n
<\/p>\n
TBPT,,0.001431,6.30<\/p>\n
<\/p>\n
<\/p>\n
<\/p>\n
! Properties of mortar<\/p>\n
<\/p>\n
ET,1,SOLID65<\/p>\n
<\/p>\n
R,1,0,0,0,0,0,0<\/p>\n
<\/p>\n
RMORE,0,0,0,0,0<\/p>\n
<\/p>\n
<\/p>\n
<\/p>\n
MP,EX,2,6528.497409<\/p>\n
<\/p>\n
MP,PRXY,2,0.16<\/p>\n
<\/p>\n
MPTEMP,2,0<\/p>\n
<\/p>\n
<\/p>\n
<\/p>\n
TB,CONCR,2,1,9<\/p>\n
<\/p>\n
TBTEMP,22<\/p>\n
<\/p>\n
TBDATA,2,0.2,0.5,0.35,3.5<\/p>\n
<\/p>\n
! Shear transfer coefficients for an open crack. <\/p>\n
<\/p>\n
! Shear transfer coefficients for a closed crack. <\/p>\n
<\/p>\n
!Uniaxial tensile cracking stress.<\/p>\n
<\/p>\n
!Uniaxial crushing stress (positive). <\/p>\n
<\/p>\n
<\/p>\n
<\/p>\n
TB,MISO,2,1,9,0<\/p>\n
<\/p>\n
TBTEMP,22<\/p>\n
<\/p>\n
TBPT,,0.0000965,0.63<\/p>\n
<\/p>\n
TBPT,,0.000279,0.75<\/p>\n
<\/p>\n
TBPT,,0.0010410,1.68<\/p>\n
<\/p>\n
TBPT,,0.0026400,2.79<\/p>\n
<\/p>\n
TBPT,,0.0034750,3.13<\/p>\n
<\/p>\n
TBPT,,0.0055680,3.91<\/p>\n
<\/p>\n
TBPT,,0.0062860,4.18<\/p>\n
<\/p>\n
TBPT,,0.0072100,4.64<\/p>\n
<\/p>\n
TBPT,,0.0798000,5<\/p>\n","protected":false},"template":"","class_list":["post-33503","topic","type-topic","status-closed","hentry"],"aioseo_notices":[],"acf":[],"custom_fields":[{"0":{"_bbp_old_topic_id":["5675"],"_bbp_old_topic_author_name_id":["Anonymous"],"_bbp_old_is_topic_anonymous_id":["false"],"_bbp_old_closed_status_id":["publish"],"_bbp_author_ip":[null],"_bbp_old_sticky_status_id":["normal"],"_bbp_likes_count":["0","0","0","0","0"],"_btv_view_count":["1264"],"_bbp_subscription":["239021"],"_bbp_topic_status":["unanswered"],"_bbp_status":["publish"],"_bbp_topic_id":["33503"],"_bbp_forum_id":["27791"],"_bbp_engagement":["160648","162950","162959","172169"],"_bbp_voice_count":["4"],"_bbp_reply_count":["15"],"_bbp_last_reply_id":["114082"],"_bbp_last_active_id":["114082"],"_bbp_last_active_time":["2020-05-11 05:30:38"]},"test":"vaidehisr781"}],"_links":{"self":[{"href":"https:\/\/innovationspace.ansys.com\/forum\/wp-json\/wp\/v2\/topics\/33503","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/innovationspace.ansys.com\/forum\/wp-json\/wp\/v2\/topics"}],"about":[{"href":"https:\/\/innovationspace.ansys.com\/forum\/wp-json\/wp\/v2\/types\/topic"}],"version-history":[{"count":0,"href":"https:\/\/innovationspace.ansys.com\/forum\/wp-json\/wp\/v2\/topics\/33503\/revisions"}],"wp:attachment":[{"href":"https:\/\/innovationspace.ansys.com\/forum\/wp-json\/wp\/v2\/media?parent=33503"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}