{"id":290206,"date":"2023-06-24T06:53:36","date_gmt":"2023-06-24T06:53:36","guid":{"rendered":"\/forum\/forums\/topic\/effect-of-surface-area-in-convection-in-steady-state-thermal-simulation\/"},"modified":"2023-06-24T07:34:43","modified_gmt":"2023-06-24T07:34:43","slug":"effect-of-surface-area-in-convection-in-steady-state-thermal-simulation","status":"closed","type":"topic","link":"https:\/\/innovationspace.ansys.com\/forum\/forums\/topic\/effect-of-surface-area-in-convection-in-steady-state-thermal-simulation\/","title":{"rendered":"Effect of Surface Area in Convection in Steady State Thermal Simulation"},"content":{"rendered":"

In theory, we know that Qconvection = hA (Ts-Ta).<\/p>\n

More surface area means more convection. What is the effect of this area in simulation? If I reduce my model size for computational efficiency by taking half of a whole body, how will the reduced area affect the thermal results?<\/p>\n

I have a solid rectangular part with a length of L, width W and thickness T. To reduce computational time, I have cut the part in half and modeled a rectangle with length L\/2, width W and thickness T. The input boundary conditions are temperature at surface, convection and radiation surface B. I need to find the temperature on surface B. Will halving the model affect the output temperature on surface B?<\/p>\n

Note: For convection, I had to input h. I have calculated h for the actual length L, and not L\/2 as h depends on characteristic length.<\/p>\n

 <\/p>\n

Image are of two rectangles with different length. All boundary conditions (Temperature, convection, radiation) are same. If Qconvection depends on Area, shouldn’t the output temperature be different? What am I missing. And if not, then can I assume that I can reduce the model size for computational efficiency?<\/p>\n

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