


{"id":249319,"date":"2023-02-10T04:32:37","date_gmt":"2023-02-10T04:32:37","guid":{"rendered":"\/forum\/forums\/topic\/double-drop-test-for-molded-pulp-packaging\/"},"modified":"2023-02-10T14:49:40","modified_gmt":"2023-02-10T14:49:40","slug":"double-drop-test-for-molded-pulp-packaging","status":"closed","type":"topic","link":"https:\/\/innovationspace.ansys.com\/forum\/forums\/topic\/double-drop-test-for-molded-pulp-packaging\/","title":{"rendered":"Double drop test for Molded Pulp Packaging"},"content":{"rendered":"<p>Dear Peteroznewman and Ansys employees,&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>I would perform the following steps as suggested by Peteroznewman to simulate a double drop test on a mold:&nbsp;<\/p>\n<p>Have two drop plates in the simulation, use Transient Structural and have two contact sets: Contact #1 for Drop Plate #1 contacting the Pulp and Contact #2 for Drop Plate #2 contacting the Pulp. Configure the Drop Plates so they are almost touching the Pulp and use an initial velocity to avoid spending time computing the free fall.<br \/>Use a series of steps and control which drop plate contact is active.<br \/>These are not the literal steps since it can take two steps to establish an initial velocity for example.<br \/>Step 1. &nbsp;Drop Plate #1 has an initial velocity, Drop Plate #2 is supported and solve transient for 100 ms.<br \/>Step 2. Time Integration Off, support Drop Plate #1, turn off Contact #1.<br \/>Step 3. Drop Plate #2 has an initial velocity and solve transient for another 100 ms.<br \/>At the end you will have made two impacts on the same Molded Pulp Package.<\/p>\n<p>&nbsp;<\/p>\n<p>However, I am facing difficulties in setting up the contact step controls. For example, I am not sure what certain things meant in the aforementioned instructions. Firstly, I am not sure if the steps indicated above are refering to time stepping controls or time stepping in analysis settings. Also by solving 100ms transient, is this value placed in the time stepping controls?&nbsp;<\/p>\n<p>Secondly, when drop plate #2 is supported does it mean that it is suppressed in the time stepping controls during the analysis?&nbsp;<\/p>\n<p>Lastly, I am trying to simulate an initial velocity of 4.23m\/s for both plates at different times. Is there a way to make this a step input instead of a ramp input? <a href=\"https:\/\/drive.google.com\/file\/d\/1FIjMly0doU8tGfQ5-9Y-v1yzJDAhM4aK\/view?usp=sharing\">https:\/\/drive.google.com\/file\/d\/1FIjMly0doU8tGfQ5-9Y-v1yzJDAhM4aK\/view?usp=sharing<\/a><\/p>\n<p><a class=\"wp-colorbox-image cboxElement\" href=\"\/forum\/wp-content\/uploads\/sites\/2\/2023\/02\/10-02-2023-1676003458-mceclip1.png\"><img decoding=\"async\" src=\"\/forum\/wp-content\/uploads\/sites\/2\/2023\/02\/10-02-2023-1676003458-mceclip1.png\"><\/a><\/p>\n<p>&nbsp;<\/p>\n","protected":false},"template":"","class_list":["post-249319","topic","type-topic","status-closed","hentry","topic-tag-mechanicalworkbench-1","topic-tag-time-dependancy","topic-tag-transient"],"aioseo_notices":[],"aioseo_head":"\n\t\t<!-- All in One SEO 4.9.10 - aioseo.com -->\n\t<meta name=\"description\" content=\"Dear Peteroznewman and Ansys employees, I would perform the following steps as suggested by Peteroznewman to simulate a double 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