{"id":159898,"date":"2021-06-28T01:24:57","date_gmt":"2021-06-28T01:24:57","guid":{"rendered":"\/forum\/forums\/topic\/why-phase-is-not-changing-in-pool-boiling-after-applying-heat-flux-at-saturation-state\/"},"modified":"2021-07-07T10:47:45","modified_gmt":"2021-07-07T10:47:45","slug":"why-phase-is-not-changing-in-pool-boiling-after-applying-heat-flux-at-saturation-state","status":"closed","type":"topic","link":"https:\/\/innovationspace.ansys.com\/forum\/forums\/topic\/why-phase-is-not-changing-in-pool-boiling-after-applying-heat-flux-at-saturation-state\/","title":{"rendered":"Why phase is not changing in pool boiling after applying heat flux at saturation state?"},"content":{"rendered":"
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Hello,<\/p>\n

I am trying to simulate heat transfer in pool boiling in 2D. Heat will transfer from a heated copper surface to saturated stagnant refrigerant. To follow same experimental setup ,copper surface is placed inside a teflon block. So, heat will be transferred to the refrigerant from the top surface of copper block only. I created 3 surfaces ( one liquid, two solids ). Liquid surface is refrigerant and one of solid surface is copper and another one is teflon.<\/p>\n

I am using Eulerian multiphase model. As refrigerant in the pool is already at saturation temperature, liquid refrigerant should turn into vapor if heat flux is applied at the bottom surface of copper block. However, I am not getting any temperature distribution in copper block and liquid volume fraction is not also changing in the pool even after applying 50kW\/m2 at the bottom of copper surface.<\/p>\n

In the cell zone condition , I see that the solid surfaces include liquid and vapor phase .But the solid surface should be copper or teflon only.<\/p>\n

Would anyone tell me if I am doing any mistake with creating surface\/materials\/cell zone conditions ? Or, suggest me any probable other mistakes.<\/p>\n

I am expecting a temperature distribution(temperature at top surface) in copper block and bubble should grow from the top surface of copper block into liquid. Teflon has very low thermal conductivity . So, heat will not propagate into the teflon block. <\/p>\n

Regards,<\/p>\n

Anadi<\/p>\n

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