{"id":395388,"date":"2024-11-26T15:54:21","date_gmt":"2024-11-26T15:54:21","guid":{"rendered":"https:\/\/innovationspace.ansys.com\/forum\/forums\/reply\/395388\/"},"modified":"2024-11-26T15:54:21","modified_gmt":"2024-11-26T15:54:21","slug":"395388","status":"publish","type":"reply","link":"https:\/\/innovationspace.ansys.com\/forum\/forums\/reply\/395388\/","title":{"rendered":"Reply To: Please help. Very important for me"},"content":{"rendered":"

<p>That information is of limited value to me.  You need to assess how those material properties affect the stress developed in your model based on the applied boundary conditions.  For example, a brief review of the properties indicates that stainless has a much lower YS than does tintanimum.  Thus, if the loading is displacement controlled (e.g., thermal expansion or forced displacement) and the developed stress exceeds the stainless YS but not the titanimum YS, then stainless will deform much easier (tangent modulus is much less than E) and not develop as much stress.  I cannot assess those conditions for you.  I do not have access to your model.  You need to examine your model and determine how the material properties affect the developed stress, but it seems feasible that for some sets fo BCs a stainless model could develop less stress.  If you do not have a background in stress analysis and cannot determine the effect the material properties have on the developed stress, you might want to run a series of test cases with modified material properties to assess how changing some properties (e.g., E, CTE, YS, tangent modulus, etc) affect the developed stresses.  Maybe with that data, you can determine why the stainless develops less stress than the titanium. <\/p><\/p>\n","protected":false},"template":"","class_list":["post-395388","reply","type-reply","status-publish","hentry"],"aioseo_notices":[],"aioseo_head":"\n\t\t\n\t\n\t\n\t\n\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t