{"id":391488,"date":"2024-10-27T08:01:39","date_gmt":"2024-10-27T08:01:39","guid":{"rendered":"https:\/\/innovationspace.ansys.com\/forum\/forums\/reply\/391488\/"},"modified":"2024-10-27T08:01:39","modified_gmt":"2024-10-27T08:01:39","slug":"391488","status":"publish","type":"reply","link":"https:\/\/innovationspace.ansys.com\/forum\/forums\/reply\/391488\/","title":{"rendered":"Reply To: Honeycomb Shear modulus Calculation based on Analysis – ASTM 273"},"content":{"rendered":"

<div>Ne yaz\u0131k ki remote olarak a\u011fda bir s\u0131k\u0131nt\u0131 oldu\u011fundan ay\u0131n 30una kadar ula\u015famayaca\u011f\u0131m modele ama detaylar\u0131 payla\u015fmak isterim. Bonded  contact kulland\u0131\u011f\u0131mda core edge ile plate’in orta k\u0131s\u0131mlar\u0131 birbirlerini tutmaktayd\u0131 bende her \u015fey program controlled’teyken. Bende bu nedenle fixed joint kullanmaya karar verdim. Modelimde facesheet yok ve Testin gerçekle\u015fme mant\u0131\u011f\u0131n\u0131 dü\u015fündü\u011füm zaman jointlerin rigit olmas\u0131n\u0131 gerekti\u011fini dü\u015fündüm. <\/div><div> <\/div><div>I supported my model with fixed support from bottom face of bottom plate(bottom and top plates are solid) then between  top face of bottom plate and bottom edge of core fixed joint, then bonded contact between walls of core, then between top edges of core and bottom face of top plate I have  fixed joint.<\/div><div> <\/div><div> <\/div><div><div>The ASTM document states that the load to be applied should cut the core diagonally. For this reason, I applied the force and displacement that I applied to the top plate by assigning a coordinate system. In addition, I wondered if there would be a difference if I applied it parallel to the plate and tried that too and observed a difference of 1 mpa in modulus, so it is not very effective.<\/div><div> <\/div><div>In addition, when I applied 500 N (it is a random number because I only need the slope in the linear region of the force displacement curve) and solved linearly, the modulus I obtained is 239 MPA, and when I only turned on the large deflection in the same model, the modulus is 212 MPa. Later, the strain rate was given as 0.0020 inc\/min in Hexcel TDS, and I applied displacement in this way and solved linearly, which I thought would be more accurate, and found the shear modulus to be 242 Mpa. Afterwards, when I turned on the large deflection in the same model, the modulus was around 220 MPa. I applied displacement in 10 steps and in the 10th step, the end time was 60 seconds.<\/div><\/div><\/p>\n","protected":false},"template":"","class_list":["post-391488","reply","type-reply","status-publish","hentry"],"aioseo_notices":[],"acf":[],"_links":{"self":[{"href":"https:\/\/innovationspace.ansys.com\/forum\/wp-json\/wp\/v2\/replies\/391488","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/innovationspace.ansys.com\/forum\/wp-json\/wp\/v2\/replies"}],"about":[{"href":"https:\/\/innovationspace.ansys.com\/forum\/wp-json\/wp\/v2\/types\/reply"}],"version-history":[{"count":0,"href":"https:\/\/innovationspace.ansys.com\/forum\/wp-json\/wp\/v2\/replies\/391488\/revisions"}],"wp:attachment":[{"href":"https:\/\/innovationspace.ansys.com\/forum\/wp-json\/wp\/v2\/media?parent=391488"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}