{"id":363088,"date":"2024-04-19T03:12:17","date_gmt":"2024-04-19T03:12:17","guid":{"rendered":"\/forum\/forums\/reply\/363088\/"},"modified":"2024-04-19T03:12:17","modified_gmt":"2024-04-19T03:12:17","slug":"363088","status":"publish","type":"reply","link":"https:\/\/innovationspace.ansys.com\/forum\/forums\/reply\/363088\/","title":{"rendered":"Reply To: Reluctance Force Calculation in an Electro-Permanent Magnetic Clamp"},"content":{"rendered":"<p>&lt;p&gt;Hello junaed.buet,&lt;\/p&gt;&lt;p&gt;&nbsp; &nbsp; &nbsp; It makes sense when the result is small because it is total force when you assign parameter force on both <strong>workpiece&nbsp;<\/strong>and&nbsp;<strong>EPMC body.&nbsp;<\/strong>&lt;\/p&gt;&lt;p&gt;&nbsp; &nbsp; &nbsp; You should calculate force on only workpiece, not both parts (total force should be zero).&lt;\/p&gt;&lt;p&gt;HDLI&nbsp;&lt;\/p&gt;<\/p>\n","protected":false},"template":"","class_list":["post-363088","reply","type-reply","status-publish","hentry"],"aioseo_notices":[],"aioseo_head":"\n\t\t<!-- All in One SEO 4.9.10 - aioseo.com -->\n\t<meta name=\"description\" content=\"Hello junaed.buet, It makes sense when the result is small because it is total force when you assign parameter force on both workpiece and EPMC body. You should calculate force on only workpiece, not both parts (total force should be zero).HDLI\" \/>\n\t<meta name=\"robots\" content=\"max-image-preview:large\" \/>\n\t<link rel=\"canonical\" href=\"https:\/\/innovationspace.ansys.com\/forum\/forums\/reply\/363088\/\" \/>\n\t<meta name=\"generator\" content=\"All in One SEO (AIOSEO) 4.9.10\" \/>\n\t\t<meta property=\"og:locale\" content=\"en_US\" \/>\n\t\t<meta property=\"og:site_name\" content=\"Ansys Learning Forum | Ansys Innovation Space\" \/>\n\t\t<meta property=\"og:type\" content=\"article\" \/>\n\t\t<meta property=\"og:title\" content=\"Reply To: Reluctance Force Calculation in an Electro-Permanent Magnetic Clamp | Ansys Learning Forum\" \/>\n\t\t<meta property=\"og:description\" content=\"Hello junaed.buet, It makes sense when the result is small because it is total force when you assign parameter force on both workpiece and EPMC body. You should calculate force on only workpiece, not both parts (total force should be zero).HDLI\" \/>\n\t\t<meta property=\"og:url\" content=\"https:\/\/innovationspace.ansys.com\/forum\/forums\/reply\/363088\/\" \/>\n\t\t<meta property=\"article:published_time\" content=\"2024-04-19T03:12:17+00:00\" \/>\n\t\t<meta property=\"article:modified_time\" content=\"2024-04-19T03:12:17+00:00\" \/>\n\t\t<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n\t\t<meta name=\"twitter:title\" content=\"Reply To: Reluctance Force Calculation in an Electro-Permanent Magnetic Clamp | Ansys Learning Forum\" \/>\n\t\t<meta name=\"twitter:description\" content=\"Hello junaed.buet, It makes sense when the result is small because it is total force when you assign parameter force on both workpiece and EPMC body. 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You should calculate force on only workpiece, not both parts (total force should be zero).HDLI","og:url":"https:\/\/innovationspace.ansys.com\/forum\/forums\/reply\/363088\/","article:published_time":"2024-04-19T03:12:17+00:00","article:modified_time":"2024-04-19T03:12:17+00:00","twitter:card":"summary_large_image","twitter:title":"Reply To: Reluctance Force Calculation in an Electro-Permanent Magnetic Clamp | Ansys Learning Forum","twitter:description":"Hello junaed.buet, It makes sense when the result is small because it is total force when you assign parameter force on both workpiece and EPMC body. 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