


{"id":343868,"date":"2024-01-09T19:48:41","date_gmt":"2024-01-09T19:48:41","guid":{"rendered":"\/forum\/forums\/reply\/343868\/"},"modified":"2024-01-09T19:48:41","modified_gmt":"2024-01-09T19:48:41","slug":"343868","status":"publish","type":"reply","link":"https:\/\/innovationspace.ansys.com\/forum\/forums\/reply\/343868\/","title":{"rendered":"Reply To: The energy problem when solving cavitation in FLUENT"},"content":{"rendered":"<p>&lt;p&gt;&lt;span class=&#8221;HwtZe&#8221; lang=&#8221;en&#8221;&gt;&lt;span class=&#8221;jCAhz ChMk0b&#8221;&gt;&lt;span class=&#8221;ryNqvb&#8221;&gt;It&rsquo;s clear, if I just turn on the power and set the temperature to 90, the fluent will calculate that way, the pump cavity will simply be filled with liquid with a temperature of 90 degrees, and there will be no difference in the calculation.&lt;\/span&gt;&lt;\/span&gt; &lt;span class=&#8221;jCAhz ChMk0b&#8221;&gt;&lt;span class=&#8221;ryNqvb&#8221;&gt;You can go in two ways, cavitation or evaporation.&lt;\/span&gt;&lt;\/span&gt; &lt;span class=&#8221;jCAhz ChMk0b&#8221;&gt;&lt;span class=&#8221;ryNqvb&#8221;&gt;So, cavitation, does it make sense to count it in this case?&lt;\/span&gt;&lt;\/span&gt; &lt;span class=&#8221;jCAhz ChMk0b&#8221;&gt;&lt;span class=&#8221;ryNqvb&#8221;&gt;90 degrees is a temperature close to boiling, it may be more legitimate to calculate with the condition of evaporation and see if the pressure drops below atm, there is a vacuum, there is possible cavitation, and if the pressure is ok, then we conditionally conclude that the pump should be pumped at this temperature&lt;\/span&gt;&lt;\/span&gt; &lt;span class=&#8221;jCAhz ChMk0b&#8221;&gt;&lt;span class=&#8221;ryNqvb&#8221;&gt;can work.&lt;\/span&gt;&lt;\/span&gt; &lt;span class=&#8221;jCAhz ChMk0b&#8221;&gt;&lt;span class=&#8221;ryNqvb&#8221;&gt;But the water doesn&#8217;t have to boil.&lt;\/span&gt;&lt;\/span&gt; &lt;span class=&#8221;jCAhz ChMk0b&#8221;&gt;&lt;span class=&#8221;ryNqvb&#8221;&gt;If there were no bubbles at the inlet, it will not boil, then cavitation and evaporation calculations are not needed.&lt;\/span&gt;&lt;\/span&gt; &lt;span class=&#8221;jCAhz ChMk0b&#8221;&gt;&lt;span class=&#8221;ryNqvb&#8221;&gt;Am I right sir?&lt;\/span&gt;&lt;\/span&gt;&lt;\/span&gt;&lt;\/p&gt;<\/p>\n","protected":false},"template":"","class_list":["post-343868","reply","type-reply","status-publish","hentry"],"aioseo_notices":[],"aioseo_head":"\n\t\t<!-- All in One SEO 4.9.10 - aioseo.com -->\n\t<meta name=\"description\" content=\"It\u2019s clear, if I just turn on the power and set the temperature to 90, the fluent will calculate that way, the pump cavity will simply be filled with liquid with a temperature of 90 degrees, and there will be no difference in the calculation. You can\" \/>\n\t<meta name=\"robots\" content=\"max-image-preview:large\" \/>\n\t<link rel=\"canonical\" href=\"https:\/\/innovationspace.ansys.com\/forum\/forums\/reply\/343868\/\" \/>\n\t<meta name=\"generator\" content=\"All in One SEO (AIOSEO) 4.9.10\" \/>\n\t\t<meta property=\"og:locale\" content=\"en_US\" \/>\n\t\t<meta property=\"og:site_name\" content=\"Ansys Learning Forum | Ansys Innovation Space\" \/>\n\t\t<meta property=\"og:type\" content=\"article\" \/>\n\t\t<meta property=\"og:title\" content=\"Reply To: The energy problem when solving cavitation in FLUENT | Ansys Learning Forum\" \/>\n\t\t<meta property=\"og:description\" content=\"It\u2019s clear, if I just turn on the power and set the temperature to 90, the fluent will calculate that way, the pump cavity will simply be filled with liquid with a temperature of 90 degrees, and there will be no difference in the calculation. 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