{"id":320648,"date":"2023-12-04T05:34:41","date_gmt":"2023-12-04T05:34:41","guid":{"rendered":"\/forum\/forums\/reply\/320648\/"},"modified":"2023-12-04T05:34:41","modified_gmt":"2023-12-04T05:34:41","slug":"320648","status":"publish","type":"reply","link":"https:\/\/innovationspace.ansys.com\/forum\/forums\/reply\/320648\/","title":{"rendered":"Reply To: How to simulation no- load and full load PM generator"},"content":{"rendered":"

<p>thank Harinath Vudumula,<\/p><\/p>\n

    \n
  1. as i have mention my design will be run as 2 mode but the major one is generator. so at full load condition ( 60,000 rpm, 5Nm and resistance load) if I want to avchieve output line voltage 380V (380V is rms of line voltage), 48A, 30KW. I need to enter  Peak value of phase voltage in the equation (ex: Va= Vpeak*sin(2*pi*f*Time-delta) ) Vpeak = (380*sqrt(2)) \/ sqrt(3) =310V, is this correct?<\/li>\n<\/ol>\n

    <p>thanks a lot <\/p><\/p>\n","protected":false},"template":"","class_list":["post-320648","reply","type-reply","status-publish","hentry"],"aioseo_notices":[],"acf":[],"_links":{"self":[{"href":"https:\/\/innovationspace.ansys.com\/forum\/wp-json\/wp\/v2\/replies\/320648","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/innovationspace.ansys.com\/forum\/wp-json\/wp\/v2\/replies"}],"about":[{"href":"https:\/\/innovationspace.ansys.com\/forum\/wp-json\/wp\/v2\/types\/reply"}],"version-history":[{"count":0,"href":"https:\/\/innovationspace.ansys.com\/forum\/wp-json\/wp\/v2\/replies\/320648\/revisions"}],"wp:attachment":[{"href":"https:\/\/innovationspace.ansys.com\/forum\/wp-json\/wp\/v2\/media?parent=320648"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}